Question

A bottle labelled with $12V{H}_2{O}_2$ contain $700$ mL solution. If a student mixes $300$ mL of water in it, the strength, normality and volume strength of final solution are:

• A. $25.5$ g/L, $1.5$ N, $8.5$ V
• B. $25.5$ g/L, $2.5$ N, $8.4$ V
• C. $25.5$ g/L, $1.5$ N, $8.4$ V
• D. None of the above

Answer 1

Answer: (C)

$25.5$ g/L, $1.5$ N, $8.4$ V

12 V means 1 L of $H_2{O}_2$ produces 12 L $O_2$. But here the volume of solution is 700 mL.

As, Volume strength $=5.6\times$ Normality
So, $12V=5.6\times$ normality

Normality ( in 1000 mL) $=\frac{12}{5.6}=2.14N$

Now, Normality in 700 mL $=\frac{2.14}{1000}\times 700=1.5N$.

Now, as we are adding water in it , so normality will remain same, i.e., 1.5 N.

Volume strength $=5.6\times$ Normality
Volume strength $=5.6\times 1.5=8.4$ V