A bottle of an aqueous H 2 O 2 solution is labelled as - 28 V - H 2 O 2 and the density of the solution in g - mL is 1-335 - Choose the correct option-A- Molality of H 2 O 2 solution is 5B- Molality of H 2 O 2 solution is 2C- Molality of H 2 O 2 solution is 4D- None of these

The correct option is B Molality of H_2O_2 solution is 2∴Molarity = Given volume strength11.2 M = 2811.2 = 2.5 M Density (d) = mass(m)Volume (v) As 1000 mL o ...

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Standard XII

Chemistry

Molarity

A bottle of a...

Question

A bottle of an aqueous $H_{2} O_{2}$ solution is labelled as $^{'} 28 V^{'}$ $H_{2} O_{2}$ and the density of the solution in $g / m L$ is $1.335$ . Choose the correct option.

Molality of

H_{2} O_{2}

solution is

2

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Molality of

H_{2} O_{2}

solution is

5

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Molality of

H_{2} O_{2}

solution is

4

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None of these

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Solution

The correct option is A Molality of $H_{2} O_{2}$ solution is $2$
$∴ Molarity = \frac{Given volume strength}{11.2}$
$M = \frac{28}{11.2} = 2.5 M$
$D e n s i t y (d) = \frac{mass(m)}{V o l u m e (v)}$
As $1000 m L$ of solution contain $2.5$ mole of $H_{2} O_{2} .$
$M a s s o f s o l u t i o n = d \times v$
$m a s s o f s o l u t i o n = 1.335 g / m L \times 1000 m L$
$\Rightarrow m a s s o f H_{2} O_{2} = M o l e s \times m o l a r m a s s o f H_{2} O_{2}$
= $2.5 m o l e \times 34 g / m o l e$
= $85 g$
$∴ Molality = \frac{m o l e s o f s o l u t e}{w e i g h t o f s o l v e n t} \times 1000$
$Molality = \frac{2.5}{1335 - 85} \times 1000$
$M o l a l i t y = 2 m$

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A bottle of an aqueous H2O2 solution is labelled as ′28 V′ H2O2 and the density of the solution in g/mL is 1.335. Choose the correct option.

A bottle of an aqueous $H_{2} O_{2}$ solution is labelled as $^{'} 28 V^{'}$ $H_{2} O_{2}$ and the density of the solution in $g / m L$ is $1.335$ . Choose the correct option.