A bouquet is in the shape of a frustum of a cone of height 15 cm. The radii of its two circular ends are 4 cm and 2 cm. Find the volume of the bouquet.

339.6

c m^{3}

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439.6

c m^{3}

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239.6

c m^{3}

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139.6

c m^{3}

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Solution

The correct option is B 439.6 $c m^{3}$
Volume of a frustum cone = $\frac{π h}{3} (R^{2} + R r + r^{2})$
$= \frac{π \times 15}{3} (4^{2} + 4 \times 2 + 2^{2})$
$= 5 π (16 + 8 + 4)$
$= 5 π \times 28$
$= 140 \times 3.14$
= $439.6 c m^{3}$

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