CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A box A contains 2 white, 3 red and 2 black balls. Another box B contains 4 white, 2 red and 3 black balls. If two balls are drawn at random, without replacement, from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability that both balls are drawn from box B is

A
716
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
932
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
78
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
916
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 716
For the bag A we can see that there are 2 white, 3 red and 2 black balls. Similarly, from bag B we have 4 white, 2 red and 3 black balls.

Probability of choosing a white and then a red ball from bag B is given by =4C1× 2C19C2

Probability of choosing a white ball then a red ball from bag A is given by =2C1× 3C17C2

So, the probability of getting a white ball and then a red ball from bag B is given by
4C1× 2C19C24C1×2C19C2+2C1× 3C17C2 =2927+29=2×718+14=716

flag
Suggest Corrections
thumbs-up
0
mid-banner-image
mid-banner-image
similar_icon
Similar questions
Join BYJU'S Learning Program
Select...
similar_icon
Related Videos
thumbnail
lock
Bayes Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
Select...