A box contain 10 mangoes out of which four are rotten. Two mangoes are taken out together. If one of them is found good and p is probability the other is also good, then value of 13p is ___.
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Solution
Let A be the event that the first mango is good and B denotes the event that the second is good. Then, P(BA)=P(A∩B)P(A) P(A∩B)=6C210C2 P(A)=6C210C2+6C1×4C110C2 ∴P(BA)=6C26C2+6C1×4C1=513