A box contains 10 screws, 3 of which are defective. Two screws are drawn at random with replacement. The probability that none of the two screws will be defective

100%

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50%

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49%

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None of these

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Solution

The correct option is C 49%
Box contains 3 defective screws and 7 non-defective screws.

The required probability = (Prob. of 1st screw non-defective) × (Prob. of 2nd screw non-defective)

$= (\frac{7}{10}) . (\frac{7}{10}) = 0.49$

${∵ D r a w i s w i t h r e p l a c e m e n t}$

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