A box contains 100 bulbs out of which 10 are defective. A sample of 5 bulbs is drawn. The probability that none is defective, is
A
(110)5
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B
(12)5
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C
(910)5
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D
910
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Solution
The correct option is C(910)5 Let X be the number of defective bulbs in a sample of 5 bulbs. Probability that a bulb is defective =p=10100=110 Then, P(X=r)=5Cr(110)r(910)5−r The required probability P(X=0)=5C0(110)0(910)5=(910)5