Question

A box contains 19 balls bearing numbers 1, 2 3, ..........19 a ball is drawn at random from the box. What is the probability that the number on the ball is divisible by 3 ?

• A. $\frac{4}{19}$
• B. $\frac{5}{19}$
• C. $\frac{6}{19}$
• D. $\frac{7}{19}$

Answer 1

The correct option is C $\frac{6}{19}$

Total outcome $=19$
Favourable outcomes=$=3,6,9,12,15,18=6$
$=\therefore$ Required probability $=\frac{6}{19}$