A box contains 20 defective items and 80 non-defective items. If two items are selected at random without replacement, what will be the probability that both items are defective?

\frac{1}{5}

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\frac{1}{25}

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\frac{20}{99}

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\frac{19}{495}

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Solution

The correct option is D $\frac{19}{495}$
Given,
Box

$\begin{matrix} 20 defective 80 non - defective \end{matrix}$

Probability that both the items are defective
$= (\frac{20}{100}) . (\frac{19}{99}) = \frac{19}{495}$

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A box contains 20 defective items and 80 non-defective items. If two items are selected at random without replacement, what will be the probability that both items are defective?

The correct option is D 19495Given, Box 20 defective80 non−defective Probability that both the items are defective =(20100).(1999)=19495

The correct option is D $\frac{19}{495}$
Given,
Box

$\begin{matrix} 20 defective 80 non - defective \end{matrix}$

Probability that both the items are defective
$= (\frac{20}{100}) . (\frac{19}{99}) = \frac{19}{495}$