A box contains 20 tickets, some are black and others are red. If a ticket is drawn at random from the box, the probability of getting a red ticket is 14. Find the number of black tickets in the box.
A
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
15
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 15 Given, probability of getting a red ticket = 14 Total no. of red ticket in the box = 20 P (drawing a red ticket )=no. of red tickets in the boxtotal no. of tickets in the box
As probability of getting red ticket is given, Assume there are 'x' no. of red tickets. Favorable no. of outcomes = x ∴14= x20 ⇒x=5 Number of black tickets in the box =20−5=15