A box contains $25$ packets of pencils. Sachin takes $7$ packets, Ajay takes $8$ packet. How many packets are left in the box?

25

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10

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18

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17

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Solution

The correct option is D $10$
Total number of packets pencils $= 25$
Number of packets pencils taken by Sachin $= 7$
Number of packets of pencils taken by Ajay $= 8$
Number of packets left $= 25 - 7 - 8 = 10$
Thus, the correct answer is $10$ .

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A box contains 25 packets of pencils. Sachin takes 7 packets, Ajay takes 8 packet. How many packets are left in the box?

The correct option is D 10Total number of packets pencils =25Number of packets pencils taken by Sachin =7Number of packets of pencils taken by Ajay =8Number of packets left =25−7−8=10Thus, the correct answer is 10.

A box contains $25$ packets of pencils. Sachin takes $7$ packets, Ajay takes $8$ packet. How many packets are left in the box?

The correct option is D $10$
Total number of packets pencils $= 25$
Number of packets pencils taken by Sachin $= 7$
Number of packets of pencils taken by Ajay $= 8$
Number of packets left $= 25 - 7 - 8 = 10$
Thus, the correct answer is $10$ .