A box contains 25 parts of which 10 are defective. Two parts are being drawn simultaneously in a random manner from the box. The probability of both the parts being good is

\frac{7}{20}

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\frac{42}{125}

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\frac{25}{29}

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\frac{5}{9}

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Solution

The correct option is A $\frac{7}{20}$
Given that
Total parts=25
Defective parts=10
So good parts=15
Required probability is
$P = \frac{15_{C_{2}}}{25_{C_{2}}} = \frac{7}{20}$

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A box contains 25 parts of which 10 are defective. Two parts are being drawn simultaneously in a random manner from the box. The probability of both the parts being good is

The correct option is A 720Given that Total parts=25 Defective parts=10 So good parts=15 Required probability is P=15C225C2=720

The correct option is A $\frac{7}{20}$
Given that
Total parts=25
Defective parts=10
So good parts=15
Required probability is
$P = \frac{15_{C_{2}}}{25_{C_{2}}} = \frac{7}{20}$