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Question

A box contains 4 blue, 5 green and 4 yellow balls. Two balls are drawn with replacement. Find the probability that the first ball is blue and the second ball is yellow.

A
113
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B
16169
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C
20169
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D
413
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Solution

The correct option is B 16169
Let A be the event that the first ball is blue
and B be the event that the second ball is yellow.
Since balls are drawn with replacement, so the
size of the sample space remains constant.
So the events A and B are independent events.

Then P(AB)=P(A).P(B) =413×413 =16169.



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