Question

A box contains $4$ red, $3$ white and $2$ black balls, three balls are drawn at random. In how many ways can balls of different colors be selected?

• A. $64$
• B. $48$
• C. $32$
• D. $24$

Answer 1

Answer: (D)

$24$

Given that $3$ balls are picked and all are must be different in color.

$\Rightarrow 1$ ball from each color must be picked combinations $={}^4{C}_1\times {}^3{C}_1\times {}^2{C}_1=4\times 3\times 2$

$=24.$

Hence, the answer is $24.$