A box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is neither red nor white?
A
56
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B
14
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C
13
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D
27
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Solution
The correct option is B14 Total number of balls in the bag =5+4+7=16
∴ Total number of elementary events = 16
There are 4 balls that are neither red nor white
∴ Favourable number of elementary events =4
Hence, P (Getting neither red nor white ball) =416=14