Question

A box contains $5$ red balls, $4$ green balls and $7$ white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is neither red nor white?

• A. $\frac{5}{6}$
• B. $\frac{1}{4}$
• C. $\frac{1}{3}$
• D. $\frac{2}{7}$

Answer 1

The correct option is B $\frac{1}{4}$

Total number of balls in the bag =$5+4+7=16$

$\therefore$ Total number of elementary events = $16$

There are 4 balls that are neither red nor white

$\therefore$ Favourable number of elementary events =$4$

Hence, P (Getting neither red nor white ball) $=\frac{4}{16}=\frac{1}{4}$