A box contains 50 balls of three different colors. 15 balls are red and 20% of the balls are blue. Find the number of balls that are neither red nor blue.

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Solution

Total number of balls $= 50$
Number of red balls $= 15$
Number of blue balls $= 20 %$ of the total number of balls
$= 20 % of 50$
$= \frac{20}{100} \times 50 = 10$
Number of balls that are neither red nor blue $= 50 - (10 + 15) = 25$

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A box contains 50 balls of three different colors. 15 balls are red and 20% of the balls are blue. Find the number of balls that are neither red nor blue.

Total number of balls =50 Number of red balls =15 Number of blue balls =20% of the total number of balls =20% of 50 =20100×50=10 Number of balls that are neither red nor blue =50−(10+15)=25

Total number of balls $= 50$
Number of red balls $= 15$
Number of blue balls $= 20 %$ of the total number of balls
$= 20 % of 50$
$= \frac{20}{100} \times 50 = 10$
Number of balls that are neither red nor blue $= 50 - (10 + 15) = 25$