A box contains 6 red and 4 white marbles. A marble is drawn and replaced three times from the box. The probability that two white marbles are drawn
A
34/125
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B
36/125
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C
38/125
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D
32/125
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Solution
The correct option is B36/125 Total balls are = 6 Red and 4 White marbles = 10 balls Case when two white marble is drawn = 2 White and 1 Red marbles W W R; W R W; R W W Probability that one white marble is drawn =3×(4C110C1)×(4C110C1)×(6C110C1)=36125