A box contains 6 red marbles numbers from 1 through 6 and 4 white marbles 12 through 15. Find the probability that a marble drawn at random is white and odd numbered.

$5$

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$\frac{1}{5}$

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$6$

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$\frac{1}{6}$

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Solution

The correct option is B
$\frac{1}{5}$

No of favourable cases = 2 {13, 15}

Total number of cases = 10

Probability = $\frac{2}{10}$ = $\frac{1}{5}$

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A box contains 6 red marbles numbers from 1 through 6 and 4 white marbles 12 through 15. Find the probability that a marble drawn at random is white and odd numbered.

The correct option is B 15 No of favourable cases = 2 {13, 15} Total number of cases = 10 Probability = 210 = 15

The correct option is B
$\frac{1}{5}$

No of favourable cases = 2 {13, 15}

Total number of cases = 10

Probability = $\frac{2}{10}$ = $\frac{1}{5}$