A box contains 8 slips of paper which are numbered 0 to 7 If one slip of paper is drawn unseen the probability of drawing a number greater than 4 is

\frac{0}{8}

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\frac{1}{8}

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\frac{1}{4}

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\frac{3}{8}

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Solution

The correct option is C $\frac{1}{4}$
Number of slips with numbers greater than 4 = 3, i.e., 5, 6, 7
$∴$ Reqd probability = $\frac{3}{8}$

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A box contains 8 slips of paper which are numbered 0 to 7 If one slip of paper is drawn unseen the probability of drawing a number greater than 4 is

The correct option is C 14Number of slips with numbers greater than 4 = 3, i.e., 5, 6, 7∴ Reqd probability = 38

The correct option is C $\frac{1}{4}$
Number of slips with numbers greater than 4 = 3, i.e., 5, 6, 7
$∴$ Reqd probability = $\frac{3}{8}$