Question

A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, the probability that it bears a perfect square number is:

• A. $\frac{1}{19}$
• B. $\frac{1}{11}$
• C. $\frac{3}{10}$
• D. $\frac{1}{10}$

Answer 1

Answer: (D)

$\frac{1}{10}$

Total number of box numbered from 1 to 90 = 90
Total number of perfect square = 9
i.e. S = (1,4,9,16,25,36,49,64,81)
P(s) = $\frac{9}{90}=\frac{1}{10}$