Question

A box contains four cards numbered as $1,2,3$ and $4$ and another box contains four cards numbered as $1,4,9$ and $16$. One card is drawn at random from each box. What is the probability of getting the product of the two numbers so obtained, more than $16$?

• A. $\frac{5}{8}$
• B. $\frac{1}{2}$
• C. $\frac{3}{8}$
• D. $\frac{1}{4}$

Answer 1

Answer: (C)

$\frac{3}{8}$

$1$	$2$
$3$	$4$

$1$	$4$
$9$	$16$

Product more than $16$
$2\times 9$
$2\times 16$
$3\times 9$
$3\times 16$
$4\times 9$
$4\times 16$
Possible cases $=6$
$Probability=\frac{6}{4\times 4}=\frac{3}{8}$.