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Question
A box follows a zigzag path to reach from point A to B. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box along the line joining A and B.
The work done on the box by the force is:
A box follows a zigzag path to reach from point A to B. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box along the line joining A and B.
The work done on the box by the force is:
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Solution
The correct option is C 10 J
Work is the product of the force acting on the body and the distance covered in the direction of the force.
Work done = Force × displacement
Here the displacement is 2 m as it is the shortest distance between two points.
Hence work done by the force = 5 x 2 = 10 J.
10 J
Work is the product of the force acting on the body and the distance covered in the direction of the force.
Work done = Force × displacement
Here the displacement is 2 m as it is the shortest distance between two points.
Hence work done by the force = 5 x 2 = 10 J.
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