A box follows a zigzag path to reach from point $A$ to $B$ . The actual length of the path is $5 m$ and the length of the straight line joining the two points is $2 m$ . If a force of $5 N$ acts on the box then the work done on the box by the force is:

5 J

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25 J

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10 J

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15 J

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Solution

The correct option is C
10 J

Work done = $F o r c e \times d i s p l a c e m e n t$
Work is the product of the force acting on the body and its displacement, so here displacement is $2 m$ as it is the shortest distance between two points. Hence work done by the force = $5 \times 2$ = $10 J$ .

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A box follows a zigzag path to reach point B from point A. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box in the direction of displacement, then the work done on the box by the force is:

A box follows a zigzag path to reach from point A to B. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box then the work done on the box by the force (in joules) is ___ .

A box follows a path to reach from point A to B. The actual length of the path is 5 m in the direction of the force. If a force of 5 N acts on the box then what is the work done by the box?

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A box follows a zigzag path to reach from point A to B. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box then the work done on the box by the force is:

The correct option is C 10 J Work done = Force×displacement Work is the product of the force acting on the body and its displacement, so here displacement is 2 m as it is the shortest distance between two points. Hence work done by the force = 5×2 = 10 J.

A box follows a zigzag path to reach from point $A$ to $B$ . The actual length of the path is $5 m$ and the length of the straight line joining the two points is $2 m$ . If a force of $5 N$ acts on the box then the work done on the box by the force is:

The correct option is C
10 J

Work done = $F o r c e \times d i s p l a c e m e n t$
Work is the product of the force acting on the body and its displacement, so here displacement is $2 m$ as it is the shortest distance between two points. Hence work done by the force = $5 \times 2$ = $10 J$ .