A box follows a zigzag path to reach point B from point A. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box in the direction of displacement, then the work done on the box by the force is:

5 J

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25 J

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10 J

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15 J

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Solution

The correct option is C
10 J

Work is the product of the force acting on the body and its displacement in the direction of the force. Here the displacement is 2 m as it is the shortest distance between point A and B. Hence work done by the force $= force \times displacement = 5 \times 2 = 10 J$

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A box follows a zigzag path to reach point B from point A. The actual length of the path is 5 m and the length of the straight line joining the two points is 2 m. If a force of 5 N acts on the box in the direction of displacement, then the work done on the box by the force is:

The correct option is C 10 J Work is the product of the force acting on the body and its displacement in the direction of the force. Here the displacement is 2 m as it is the shortest distance between point A and B. Hence work done by the force =force×displacement = 5×2=10 J

The correct option is C
10 J

Work is the product of the force acting on the body and its displacement in the direction of the force. Here the displacement is 2 m as it is the shortest distance between point A and B. Hence work done by the force $= force \times displacement = 5 \times 2 = 10 J$