Question

A box has 390 bulbs. Out of this 26 are defective. A bulb is chosen at random. Find the probability of the bulb chosen, not being defective :

• A. $\frac{1}{15}$
• B. $\frac{14}{15}$
• C. $\frac{3}{20}$
• D. $\frac{2}{29}$

Answer 1

The correct option is B $\frac{14}{15}$

A box has $390$ bulbs.

Out of this $26$ are defective

Bulb chosen, not being defective $=390-26=364$

The probability is $P\left(E\right)=\frac{364}{390}=\frac{14}{15}$