A box has 4 red socks and 6 yellow socks. What is the probability of picking a red sock?

\frac{1}{5}

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\frac{2}{5}

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\frac{3}{5}

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\frac{2}{7}

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Solution

The correct option is B $\frac{2}{5}$
We know, Probability of an event E is given by
P(E) = $\frac{N u m b e r o f f a v o u r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s}$

Here, the event E is picking a red sock.
Favourable outcomes = 4 (Since there are 4 red socks.)
Total number of outcomes = 10 (Since there are a total of 10 socks)

P(E) = $\frac{4}{10}$ = $\frac{2}{5}$

Suggest Corrections

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5 r e d

3 b l u e

2 g r e e n

$P (R e d) = \frac{1}{2}$
$P (B l u e) = \frac{1}{10}$
$P (G r e e n) = \frac{1}{5}$
$P (R e d) = \frac{1}{2}$
$P (B l u e) = \frac{1}{5}$
$P (G r e e n) = \frac{1}{10}$
$P (R e d) = \frac{1}{2}$
$P (B l u e) = \frac{3}{10}$
$P (G r e e n) = \frac{1}{5}$

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