A box is of dimension $54 c m \times 45 c m \times 300 c m$ . How many soaps can be fitted in it if each measure $9 c m \times 5 c m \times 3 c m$ .

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Solution

Volume of the box $= 54 c m \times 45 c m \times 300 c m = 729000 c m^{3}$
Volume of each soap $= (9 \times 5 \times 3) c m^{3} = 135 c m^{3}$
No of soaps will be fitted in the box $= (\frac{729000}{135}) = 5400$

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A box is of dimension 54 cm×45 cm×300 cm. How many soaps can be fitted in it if each measure 9 cm×5 cm×3 cm.

Volume of the box=54 cm×45 cm×300 cm=729000 cm3Volume of each soap =(9×5×3) cm3=135 cm3No of soaps will be fitted in the box=(729000135)=5400

A box is of dimension $54 c m \times 45 c m \times 300 c m$ . How many soaps can be fitted in it if each measure $9 c m \times 5 c m \times 3 c m$ .

Volume of the box $= 54 c m \times 45 c m \times 300 c m = 729000 c m^{3}$
Volume of each soap $= (9 \times 5 \times 3) c m^{3} = 135 c m^{3}$
No of soaps will be fitted in the box $= (\frac{729000}{135}) = 5400$