Question

A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is ${60}^{\circ }$, then the coefficient of static friction between the box and the plane is.

• A. 2.732
• B. 1.732
• C. 0.267
  
• D. 0.176

Answer 1

The correct option is B 1.732

$f=mgsin\theta \to$ (1)
$f=\mu N=\mu mgcos\theta \to \left(2\right)$
From (1) and (2)
$\mu =tan\theta =tan{60}^{\circ }=\sqrt{3}=1.732$