Question

A box measures $80\text{cm}$ in length, $60\text{cm}$ in breadth and $40\text{cm}$ in height. How many cubical boxes of $20\text{cm}$ length can be arranged in it ?

Answer 1

Given:-

Length of box, $l=80\text{cm}$

Breadth of box, $b=60\text{cm}$

Height of box, $h=40\text{cm}$

Length of each side of cubical boxes, $a=20\text{cm}$

Now,

$\text{No. of cubical boxes}=\frac{\text{Volume of cuboidal boxes}}{\text{Volume of cubical boxes}}$

$=\frac{l\times b\times h}{a^3}$

$=\frac{80\times 60\times 40}{20\times 20\times 20}$

$=6\times 4$

$=24\text{boxes}$

Hence, the number of cubical boxes which can be arranged in the cuboidal boxes is equal to $24$.