Question

A box of mass 2 kg is pushed from rest such that it acquires a velocity of 10 m/s in 5 seconds. The average force applied on the box is

• A. 2 N
• B. 4 N
• C. 8 N

Answer 1

The correct option is B 4 N

Here,
Initial velocity, u = 0 m/s
Final velocity, v = 10 m/s
Time taken, t = 5 s
From the first equation of motion,
v = u + at
a = $\frac{v-u}{t}$
a = $\frac{10-0}{5}$
⇒ a = $2m/s^2$
From Newton’s second law, F = ma Here, m = 2 kg
⇒ F = 2 ✕ 2 = 4 N