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Question

A box of mass 5kg is kept inside a lift. Lift starts from rest and moves upward at a speed of 1ms1. What is work done by normal force in first 5s? [g=10ms2]

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Solution

Normal force R=mg=5×10=50 N
Initial speed u=1 m/s
t=5 s
Displacement S=ut=1×5=5 m
Work done W=R×S=50×5=250 J

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