Question

A box of mass m is attached to a spring on a frictionless surface. The spring is compressed from its equilibrium position, $B$, to point $A$, a distance $x$ from $B$. Point $C$ is also a distance $x$ from $B$, but in the opposite direction. When the box is released from position $A$, Find out the points at which box's velocity is maximum ?

• A. $A$
• B. $B$
• C. $C$
• D. Both $A$ and $C$
• E. Both $A$ and $B$

Answer 1

The correct option is B $B$

When the box is released , it will do SHM ,because by Hook's law restoring force is directly proportional to displacement and opposite in direction now velocity $v$ in SHM for displacement $x$ is given by

$v=\omega \sqrt{a^2-x^2}$ where $\omega$ = angular frequency and $a=$amplitude

from above relation it is clear that velocity $v$ will be maximum at a point where $x$ is minimum i.e. $x=0$

and $x=0$ shows the mean position $B$.