Question

A box of mass M is gently placed over a conveyor belt moving linearly with speed v. The coefficient of friction between the box and conveyer belt is u . The box will start sliding on the belt after travelling a distance of ?

Answer 1

Dear Student
The initial velocity of box relative to the belt is v in m/s backward direction. (opposite to motion of belt) that is -v m/s. The box experience maximum frictional force F=μR=μMgF=μR=μMg
Therefore a=Force/ mass
a= μmg/m
=μg in forward direction
Let the box come to rest in distance S
v²=u²+2as
0=(−v)²+2a.s
s = - v² /μg
We sign shows the box moves in opposite direction of motion of belt

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