A box of the mass $40 kg$ is kept on a floor. Sanjay is trying to push it from the left and Harish is trying to push it from the right.The forces exerted by them are $25 N$ and $35 N$ respectively.However, the box remains stationary on the floor. Find the force of friction acting on the box.

10 N, Leftwards

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10 N, Rightwards

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25 N, Leftwards

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25 N, Rightwards

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Solution

The correct option is B $10 N, Rightwards$

Apart from the forces of $25 N$ and $35 N$ exerted by Sanjay and Harish, a force of friction $f$ acts on the box, exerted by the floor.
As the box remains at rest, the resultant force on it must be zero by Newton's first law.
It is clear that resultant of the force applied by the two people is $35 N - 25 N = 10 N,$ towards the left
So, the force of friction is towards the right and its magnitude is $10 N$ .

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A box of the mass 40 kg is kept on a floor. Sanjay is trying to push it from the left and Harish is trying to push it from the right.The forces exerted by them are 25 N and 35 N respectively.However, the box remains stationary on the floor. Find the force of friction acting on the box.

A box of the mass $40 kg$ is kept on a floor. Sanjay is trying to push it from the left and Harish is trying to push it from the right.The forces exerted by them are $25 N$ and $35 N$ respectively.However, the box remains stationary on the floor. Find the force of friction acting on the box.