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Question

A box of washing soda has 1.43 kg of Na2CO3.10H2O (molar mass = 286 g/mol). The box was sent to the godown and it weighed only 1.34 kg on arrival. An independent analyst says that the box contains the correct mass of sodium carbonate, but that it has lost the water of crystallization. What is the composition of the washing soda received by the godown?

A
Na2CO3.1.3H2O
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B
Na2CO3.1.7H2O
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C
Na2CO3.8.3H2O
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D
Na2CO2.8.9H2O
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Solution

The correct option is C Na2CO3.8.3H2O
Number of moles in 1430 g of Na2CO3.10H2O is 1430286
Let the composition of sodium carbonate received be, Na2CO3.xH2O. This weighs 1340 g
1430286×(106+18x)=1340
x=9
where molar mass of anhydrous Na2CO3 is 106 g/mol

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