A box of weight $150 k g f$ has $1.47 k J$ of gravitational potential energy stored in it. Find the height of the box above the ground. Take $g = 9.8 N k g^{- 1}$ .

10 m

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4.9 m

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2.45 m

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1 m

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Solution

The correct option is D $1 m$
Weight of the body $= 150 k g f$
$∴$ mass of the body, $m = 150 k g$
Given, $U = 1.47 k J = 1470 J, g = 9.8 N k g^{- 1} = 9.8 m s^{- 2}$
Let the height above ground be $h$ .
So, $U = m g h$
or, $1470 = 150 \times 9.8 \times h$
or, $h = \frac{1470}{150 \times 9.8} = 1 m$

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