A boy applies a minimum force of 5 N on the edge of a 2 m wide door to open it. How much minimum force should he apply to open the door from its midpoint?

2 N

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5 N

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10 N

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20 N

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Solution

The correct option is C 10 N
Force applied at the edge, $F_{1} = 5 N$
Distance of $F_{1}$ froom pivot, $r_{1} = 2 m$
Force applied at mid point $= F_{2}$
Distance of pivot from mid point, $r_{2} = 1 m$
To open the door moment of force in both the cases must be equal
$F_{1} \times r_{1} = F_{2} \times r_{2}$
$5 \times 2 = F_{2} \times 1$
$F_{2} = 10 N$

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