A boy begins to walk eastward along a street in front of his house and the graph of his position from home is shown in the following figure. His average speed for the whole time interval is equal to?

8

m/min

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6

m/min

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\frac{8}{3}

m/min

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2

m/min

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Solution

The correct option is B $6$ m/min
$A v e r a g e S p e e d = \frac{T o t a l d i s t a n c e c o v e r e d}{T o t a l t i m e t a k e n} T o t a l d i s t a n c e c o v e r e d = 40 + 40 + 20 + 20 = 120 m e t e r s T o t a l t i m e t a k e n = 20 m i n u t e s . T h e r e f o r e A v e r a g e S p e e d = \frac{120 m}{20 m} = 6 m / m i n$

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A boy begins to walk eastward along a street in front of his house and the graph of his position from home is shown in the following figure. His average speed for the whole time interval is equal to?

The correct option is B 6 m/minAverageSpeed=TotaldistancecoveredTotaltimetakenTotaldistancecovered=40+40+20+20=120metersTotaltimetaken=20minutes.ThereforeAverageSpeed=120m20m=6m/min