A boy bought a book for ₹x and sold it for ₹26. If his loss was x percent, find the second degree equation from which we can find cost price of the book.

(A) $x^{2} - 100 x + 3600 = 0$
(B) $2 x^{2} - 100 x + 2600 = 0$
(C) $x^{2} - 100 x + 2600 = 0$
(D) $x^{2} - 200 x + 2600 = 0$
$[1]$

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Solution

Answer: Option C
S.P = ₹26

C.P = ₹x

Loss% = x%

$x = \frac{x - 26}{x} \times 100$

$\Rightarrow x^{2} = 100 x - 2600$

$\Rightarrow x^{2} - 100 x + 2600 = 0$

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A boy bought a book for ₹x and sold it for ₹26. If his loss was x percent, find the second degree equation from which we can find cost price of the book. (A) x2−100x+3600=0 (B) 2x2−100x+2600=0 (C) x2−100x+2600=0 (D) x2−200x+2600=0 [1]

Answer: Option C S.P = ₹26 C.P = ₹x Loss% = x% x=x−26x×100 ⇒x2=100x−2600 ⇒x2−100x+2600=0

A boy bought a book for ₹x and sold it for ₹26. If his loss was x percent, find the second degree equation from which we can find cost price of the book.

(A) $x^{2} - 100 x + 3600 = 0$
(B) $2 x^{2} - 100 x + 2600 = 0$
(C) $x^{2} - 100 x + 2600 = 0$
(D) $x^{2} - 200 x + 2600 = 0$
$[1]$

Answer: Option C
S.P = ₹26

C.P = ₹x

Loss% = x%

$x = \frac{x - 26}{x} \times 100$

$\Rightarrow x^{2} = 100 x - 2600$

$\Rightarrow x^{2} - 100 x + 2600 = 0$