A boy buys oranges at $3$ for $R s . 10$ . He will sell them at $5$ for $R s . 20$ . In order to make a profit of $R s . 1.00$ , he must sell

67

oranges

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150

oranges

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

200

oranges

No worries! We‘ve got your back. Try BYJU‘S free classes today!

An infinite number of oranges

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $150$ oranges
The profit on each orange sold is $4 - 3 \frac{1}{3} = \frac{2}{3} p a i s e$
$∴ \frac{2}{3} n = 100, n = 150$ .

Suggest Corrections

Similar questions

A man buys oranges at Rs $5$ a dozen and an equal number at Rs $4$ a dozen. He sells them at Rs $5.50$ a dozen and makes a profit of Rs $50$ . How many oranges does he buy?

A fruit-seller buys oranges at 4 for Rs.3 and sells them at 3 for Rs.4. Find his profit percent.

Q. A fruit-seller buys oranges at

4

for Rs.

3

and sell them at

3

for Rs.

4

. Find his profit percentage.

Q. A fruit seller loses 10% by selling oranges at 26 for Rs. 25. How many oranges should he sell for Rs. 5 to gain 17 per cent ?

Q. A fruit seller losses

10 %

by selling

26

oranges for Rs.

25

. The number of oranges he should sell for Rs.

5

each to gain

17 %

Join BYJU'S Learning Program

A boy buys oranges at 3 for Rs.10. He will sell them at 5 for Rs.20. In order to make a profit of Rs.1.00, he must sell

The correct option is C 150 orangesThe profit on each orange sold is 4−313=23paise∴23n=100,n=150.

A boy buys oranges at $3$ for $R s . 10$ . He will sell them at $5$ for $R s . 20$ . In order to make a profit of $R s . 1.00$ , he must sell

The correct option is C $150$ oranges
The profit on each orange sold is $4 - 3 \frac{1}{3} = \frac{2}{3} p a i s e$
$∴ \frac{2}{3} n = 100, n = 150$ .