Question

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that boy throw the same stone up will be

• A. 20 m
• B. $20\sqrt{2}m$
• C. 10 m
• D. $10\sqrt{2}m$

Answer 1

The correct option is A 20 m

For vertically projected up body maximum height (H) is given as

$H=\frac{u^2}{\left(2g\right)}.......\left(1\right)$

For the same bocy with same initial velocity the horizontal distance traveled when thrown at an angle$\left(\theta \right)$ is given as

$R=\frac{u^2}{g}...........\left(2\right)$

Compare equations $1$ and $2$

$R=2H$

$R=2\times 10$

$R=20$ m