Question

A boy can throw a stone up to maximum height of $10$cm. The maximum horizontal distance that the boy can throw the same stone up to will be?

Answer 1

Given vertical height = 10m. if we took it as max vertical height

then,$\frac{u^2}{2g}=10m=>\frac{u^2}{2g}=20$

As horizontal projectile range $=u^2\sin \frac{2\theta }{g}$

So, range is maximum when$\theta =45degrees$

Hence, maximum horizontal range is $\frac{u^2}{2g}=20m$