A boy contains 1Rs coins and 2 Rs coins whose total value is 70 R's. If the number of 1Rs coins is five times that of 2 Rs coins ,find the number of coins of each type.
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Solution
Let the number of 1Rs coins be 5x And the number of 2Rs coins be x total value of coins =70 so,1×5x +2×x=70 . 5x+2x=70 . 7x=70 . x=10 therefore no. Of 1rs coins=5x=5×10=50 . And no. Of 2rs coins=x=10