A boy drops a stone from a cliff reaches the ground in 8 seconds .Calculate final velocity of stone and height of cliff ( take a =9.8m/s?)

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Solution

Dear Student,

$u = 0 m / s t = 8 \sec acceleartion due to gravity, g = 9.8 m / s^{2} v = u + gt v = 0 + 9.8 \times 8 = 78.4 m / s height, h = ut + \frac{1}{2} {gt}^{2} h = 0 \times 8 + \frac{1}{2} \times 9.8 \times 8 \times 8 h = 313.6 m$

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A boy drops a stone from a cliff reaches the ground in 8 seconds .Calculate final velocity of stone and height of cliff ( take a =9.8m/s?)

Dear Student, u=0 m/st=8 secacceleartion due to gravity, g=9.8 m/s2v=u+gtv=0+9.8×8=78.4 m/sheight, h=ut+12gt2h=0×8+12×9.8×8×8h=313.6 m

Dear Student,

$u = 0 m / s t = 8 \sec acceleartion due to gravity, g = 9.8 m / s^{2} v = u + gt v = 0 + 9.8 \times 8 = 78.4 m / s height, h = ut + \frac{1}{2} {gt}^{2} h = 0 \times 8 + \frac{1}{2} \times 9.8 \times 8 \times 8 h = 313.6 m$