Question

A boy has $8$ trousers $10$ shirts. In how many ways can he select a shirt and a trouser?

• A. $80$
• B. $8!\times 10!$
• C. $64$
• D. $8{!}^2$

Answer 1

The correct option is A $80$

No of ways of selecting a trouser ${}^8{c}_1=8$

No of ways of selecting a shirt ${}^{10}{c}_1=10$

Total No of ways $=8\times 10=80$