Question

A boy has a few coins of denominations $50$ paise, $25$ paise and $10$ paise in the ratio of $1:2:3$. If he total amount of the coins is Rs. $6.50$, then the number of $10$ paise coins is -

• A. $5$
• B. $10$
• C. $15$
• D. $20$

Answer 1

Answer: (C)

$15$

Ratio of the coins : $1:2:3$
Let no. of 50 paise coins $=x$
Value of 50 paise coins $=\frac{x}{2}=$Rs.$\frac{x}{2}$
No. of 25 paise coins $=2x$
Value of 25 paise coins $=\frac{2x}{4}=$Rs.$\frac{x}{2}$
No. of 10 paise coins $=3x$
Value of 10 paise coins $=\frac{3x}{10}=$Rs. $\frac{3x}{10}$
Total value of the coins $=$ Rs.$6.50$
$\left(\frac{x}{2}\right)+\left(\frac{x}{2}\right)+\left(\frac{3x}{10}\right)=6.50$
$\Rightarrow \frac{(5x+5x+3x)}{10}=6.50$
$\Rightarrow 13x=65$
$\Rightarrow x=5$
Then no. of 10 paise coins $=3x=3\times 5=15$