Question

A boy is at a distance of $70$ $m$ from a tree makes an angle of elevation of ${60}^{\circ }$ with the top of the tree. What is the height of the tree?

Answer 1

Let height of the tree $=h$
Given, distance $AB=70$ $m$
and angle of elevation $\angle B={60}^{\circ },\sqrt{3}=1.73$
$\therefore$ In right angled $△ABT$, we have
$\tan B=\frac{AT}{AB}$
$\Rightarrow \tan {60}^{\circ }=\frac{h}{70}$
$\Rightarrow \sqrt{3}=\frac{h}{70}$
$\Rightarrow h=70\times \sqrt{3}$
$=70\times 1.73$
$=121.10$ $m$
$\therefore$ height of the tree $=121.10$ $m$.