A boy is sitting on a swing at a maximum height of 5m above the ground. When the swing passes through the mean position which is 2m above the ground its velocity is approximately:

7.6 m / s e c

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9.8 m / s e c

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6.26 m / s e c

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None of these

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Solution

The correct option is B $7.6 m / s e c$
Loss in potential energy is converted into the potential energy as,
$m g h = 0.5 m v^{2}$
$v^{2} = 2 \times 10 \times (5 - 2)$
$v = \sqrt{60} = 7.6 m / s$

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A boy is sitting on a swing at a maximum height of 5m above the ground. When the swing passes through the mean position which is 2m above the ground its velocity is approximately:

The correct option is B 7.6m/secLoss in potential energy is converted into the potential energy as,mgh=0.5mv2v2=2×10×(5−2)v=√60=7.6m/s

The correct option is B $7.6 m / s e c$
Loss in potential energy is converted into the potential energy as,
$m g h = 0.5 m v^{2}$
$v^{2} = 2 \times 10 \times (5 - 2)$
$v = \sqrt{60} = 7.6 m / s$