A boy is standing in a lift. The force on the floor of the lift due to the weight of the boy becomes zero:

When the lift moves down with an acceleration of

9.8 m s^{- 2}

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When the lift moves down with an acceleration

9.8 m s^{- 2}

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When the lift is not moving

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None of these

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Solution

The correct option is B When the lift moves down with an acceleration $9.8 m s^{- 2}$
When the lift moves down the reaction will be in the upward direction. Therefore tension mg acts down and reaction mg acts in the opposite direction. The net force acting will be zero.

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A boy is standing in a lift. The force on the floor of the lift due to the weight of the boy becomes zero:

The correct option is B When the lift moves down with an acceleration 9.8 ms−2When the lift moves down the reaction will be in the upward direction. Therefore tension mg acts down and reaction mg acts in the opposite direction. The net force acting will be zero.

The correct option is B When the lift moves down with an acceleration $9.8 m s^{- 2}$
When the lift moves down the reaction will be in the upward direction. Therefore tension mg acts down and reaction mg acts in the opposite direction. The net force acting will be zero.